float.as_integer_ratio() Exact ratio
Last updated: 2026-09-22
float.as_integer_ratio() Exact ratio
float.as_integer_ratio() returns an exact (numerator, denominator) pair.
| Category | Number Methods |
|---|---|
| Kind | Built-in Type Method |
| Python Version | all |
📝 Syntax
float.as_integer_ratio()
Returns:tuple. An exact (numerator, denominator) pair for the float.
Mutates the original:No (returns a new object)
💥 Raises
OverflowError— Raised when the float is infinite (inf).ValueError— Raised when the float is NaN.
▶ Example
Edit the code, press Run, and see the result in the output panel:
Output:
(1, 2)
(1, 4)
💡 Related Cases
More case studies coming soon — check back later.
❓ FAQ
QWhat does as_integer_ratio() return?
AAn exact (numerator, denominator) tuple: 0.5 returns (1, 2). Note that it represents the exact value of the binary float.
QWhy does the ratio for 0.1 look strange?
A0.1 cannot be represented exactly in binary; it returns the exact fraction of its actually stored value, so the numerator and denominator can be long.
QWhat happens with inf and NaN?
Afloat('inf').as_integer_ratio() raises OverflowError; NaN raises ValueError.